Five Rings interview questions

How Five Rings's process runs, as candidates and the firm describe it, and the questions candidates report, each with a worked solution. Free, no sign-up.

Practise these in the app Mock interview

How Five Rings interviews

Sources: Glassdoor: Five Rings quant trader

Questions (11)

Try each one before opening the solution. Interviewers change the numbers, so learn the method.

Quantitative Trader · Technical · Game theory · reported by a candidate

A two-card poker game: you're dealt an ace or a queen at random, and only you see it. Each player has put $1 in the pot. You may raise $1 or check (checking goes straight to showdown, where the ace wins). If you raise, your opponent can call $1 or fold. Your opponent knows your strategy.

The reported wording is ambiguous about the deal. This is the standard version of the game it describes, the classic bluffing model.

  1. (a) With an ace you always raise. With a queen, what bluffing frequency q makes your opponent indifferent between calling and folding?
    Answer and worked solution

    Answer: 1/3 ≈ 0.33333

    Key idea. At equilibrium your bluffing frequency makes the opponent indifferent between calling and folding.

    1. You raise every ace and a fraction q of queens. A raise is a bluff with probability q/(1 + q).
    2. Calling wins $2 against a bluff and loses $2 against an ace; folding loses the $1 ante.
    3. Indifference: 2·q/(1 + q) − 2·1/(1 + q) = −1.
    4. Multiply by (1 + q): 2q − 2 = −1 − q, so 3q = 1, q = 1/3.

    Check. Bluffs are 1/4 of your raises. Relative to folding, calling gains $3 against a bluff and loses $1 against an ace, so it breaks even exactly when a quarter of raises are bluffs.

  2. (b) How often should your opponent call to make your bluff break even?
    Answer and worked solution

    Answer: 2/3 ≈ 0.66667

    Key idea. Now make yourself indifferent, with a queen, between bluffing and checking.

    1. Checking a queen goes to showdown and loses $1.
    2. Bluffing: +$1 if they fold (prob 1 − c), −$2 if they call (prob c): (1 − c) − 2c.
    3. Set 1 − 3c = −1: c = 2/3.

    Check. If they called less, bluffing would be profitable; more, and you'd stop bluffing.

  3. (c) What is the game worth to you per hand?
    Answer and worked solution

    Answer: 1/3 ≈ 0.33333

    Key idea. Average over the card you're dealt, using the equilibrium strategies.

    1. Ace: you raise; they call 2/3 (+$2) or fold 1/3 (+$1): (2/3)·2 + (1/3)·1 = 5/3.
    2. Queen: you're indifferent, so value it as checking: −$1.
    3. Game value = ½(5/3) + ½(−1) = ½ × 2/3 = $1/3 per hand.

    Check. Positive, because you have information they don't, and you use it with correctly mixed bluffs.

Interviewers may push further: What changes if the raise size is $2?

Source: Glassdoor · Try it in the app →

Quant Trader Intern · First round · Mental maths · reported by a candidate

Rapid estimates, as reported from a Five Rings first round.

  1. (a) The tenth root of 10
    Answer and worked solution

    Answer: 1.2589

    Key idea. Use logs.

    1. log₁₀(answer) = 0.1.
    2. log₁₀ 2 ≈ 0.301, so 100.1 ≈ 21/3, the cube root of 2.
    3. ≈ 1.26.

    Check. 1.26³ ≈ 2.0.

  2. (b) log base 1.2 of 3
    Answer and worked solution

    Answer: 6.0257

    Key idea. Change of base.

    1. ln 3/ln 1.2 ≈ 1.099/0.182.
    2. ≈ 6.0.

    Check. 1.2⁶ ≈ 2.99.

  3. (c) The number of digits in 50!
    Answer and worked solution

    Answer: 65

    Key idea. Digits = ⌊log₁₀ 50!⌋ + 1. Use Stirling.

    1. log₁₀ n! ≈ n log₁₀(n/e) + ½ log₁₀(2πn).
    2. 50 × log₁₀ 18.39 ≈ 50 × 1.2646 = 63.2; ½ log₁₀ 314 ≈ 1.25.
    3. ≈ 64.5, so 65 digits.
  4. (d) The water in an Olympic pool, in cubic metres
    Answer and worked solution

    Answer: 2500

    Key idea. Volume = length × width × depth.

    1. 50 m × 25 m × about 2 m.
    2. ≈ 2,500 m³ (2.5 million litres).

Interviewers may push further: A baby elephant weighs roughly how much? (About 100 kg at birth.)

Source: Glassdoor · Try it in the app →

Quant Trader Intern · First round · Combinatorics · reported by a candidate

You cut a pizza with straight cuts.

  1. What is the most pieces you can get with 10 cuts?
    Answer and worked solution

    Answer: 56

    Key idea. The k-th cut can cross all k − 1 earlier cuts, adding k pieces.

    1. Start with 1 piece.
    2. Add 1 + 2 + … + 10 = 55.
    3. 56 pieces.

    Check. Formula: 1 + n(n + 1)/2.

Source: Glassdoor · Try it in the app →

Quant Trader Intern · First round · Expected value · reported by a candidate

Roll a die. If it shows 4 or less, roll a second die too. You're paid the total of the dice you rolled.

  1. What is the expected payout?
    Answer and worked solution

    Answer: 35/6 ≈ 5.8333

    Key idea. Linearity: the first die plus the second die times P(it's rolled).

    1. First die: 3.5.
    2. Second die: rolled with probability 4/6, worth 3.5: 7/3.
    3. Total = 3.5 + 7/3 = 35/6 ≈ 5.83.

Interviewers may push further: The interviewer then let the candidate choose the dice sizes and order. What would you ask before answering?

Source: Glassdoor · Try it in the app →

Assistant Trader · Interview · Probability · reported by a candidate

The probability of seeing a car pass in one minute is 1/4.

Assume cars arrive at a steady rate, independently (a Poisson process).

  1. What is the probability of seeing a car in 30 seconds?
    Answer and worked solution

    Answer: 0.13397

    Key idea. Assume cars arrive independently at a steady rate (a Poisson process).

    1. P(no car in 1 min) = 3/4 = P(no car in 30 s)².
    2. P(no car in 30 s) = √0.75 ≈ 0.866.
    3. P(at least one) ≈ 0.134.

    Check. A bit more than half of ¼.

    Trap. Answering 1/8.

Source: Glassdoor · Try it in the app →

Trader · Interview · Random walks · reported by a candidate

A has $6 and B has $4. They bet $1 on fair coin flips until one of them is broke.

  1. What is the probability A ends up with all $10?
    Answer and worked solution

    Answer: 0.6

    Key idea. A fair game: A's expected wealth stays $6 throughout.

    1. At the end A has $10 (prob p) or $0.
    2. 10p = 6.
    3. p = 0.6.

    Check. Your chance is your share of the total money.

Interviewers may push further: Expected number of flips? (6 × 4 = 24.)

Source: Glassdoor · Try it in the app →

Quantitative Trader Intern · Interview · Random walks · reported by a candidate

A coin lands heads with probability 2/3. You toss it until the number of heads first exceeds the number of tails by 2.

  1. What is the expected number of tosses?
    Answer and worked solution

    Answer: 6

    Key idea. Wald's identity: target = drift × E[tosses], because steps of ±1 hit +2 exactly.

    1. Drift per toss = 2/3 − 1/3 = 1/3.
    2. 2 = (1/3) × E[N].
    3. E[N] = 6.

    Check. Or: getting up by one takes E₁ = 1 + (1/3)(2E₁), so E₁ = 3; you need it twice.

Source: Glassdoor · Try it in the app →

Trader · Interview · Behavioural · reported by a candidate

Behavioural questions candidates report:

Answer one out loud, as you would in the interview.

Model answer

Three parts, about a minute each. Why trading: a specific moment you got hooked (a game, a market you followed, a decision under uncertainty), not "I like maths". Why this firm: something concrete about how it trades or trains people, ideally from talking to someone there or from its own material. Why you: evidence you already think in probabilities and react well to being wrong. Avoid anything about money or prestige.

Source: Glassdoor · Try it in the app →

Quant Research intern · Interview · Probability · reported by a candidate

X and Y are independent standard normal random variables.

We take X and Y independent standard normal.

  1. What is E[max(X, Y)]?
    Answer and worked solution

    Answer: 0.56419

    Key idea. max(X, Y) = (X + Y)/2 + |X − Y|/2.

    1. E[(X + Y)/2] = 0.
    2. X − Y ~ N(0, 2), and E|Z| = σ√(2/π) for Z ~ N(0, σ²): E|X − Y| = √2 × √(2/π) = 2/√π.
    3. E[max] = ½ × 2/√π = 1/√π ≈ 0.564.

    Check. Positive, and less than 1: the larger of two standard normals is usually around half a standard deviation up.

Source: Wall Street Oasis: Five Rings interview reports · Try it in the app →

Quant intern · Interview · Mental maths · reported by a candidate

Find the length of the curve y = x² from x = 0 to x = 9.

  1. Its length (to the nearest whole number, or better)?
    Answer and worked solution

    Answer: 82.021

    Key idea. Arc length ∫√(1 + y′²) dx, with y′ = 2x.

    1. L = ∫₀⁹ √(1 + 4x²) dx = [x√(1 + 4x²)/2 + asinh(2x)/4]₀⁹.
    2. = 9√325/2 + asinh(18)/4 ≈ 81.12 + 0.90.
    3. ≈ 82.0.

    Check. Quick bound: the curve rises 81 while moving 9 across, so its length is a bit more than √(81² + 9²) ≈ 81.5.

Source: Wall Street Oasis: Five Rings interview reports · Try it in the app →

Quant Trader · Interview · Mental maths · reported by a candidate

Quick estimates reported from Five Rings interviews.

  1. (a) 33.4
    Answer and worked solution

    Answer: 41.9

    Key idea. Split the exponent.

    1. 33.4 = 27 × 30.4.
    2. 30.4 = e0.4 × 1.0986 = e0.439 ≈ 1.552.
    3. 27 × 1.552 ≈ 41.9.

    Check. Between 3³ = 27 and 3³·⁵ = 27√3 ≈ 46.8.

  2. (b) A point is uniform in a disc of radius 1. Its average distance from the centre?
    Answer and worked solution

    Answer: 2/3 ≈ 0.66667

    Key idea. Distance from the centre has density 2r (area grows with radius).

    1. P(R ≤ r) = r², so the density is 2r.
    2. E[R] = ∫₀¹ r × 2r dr = 2/3.

    Check. More than ½, because most of a disc's area is near its edge.

    Trap. Answering ½.

Source: Wall Street Oasis: Five Rings interview reports · Try it in the app →

Other firms

Jane Street · SIG (Susquehanna) · Optiver · IMC · Citadel / Citadel Securities · Two Sigma · Flow Traders · Maven Securities · Wincent · Akuna Capital · Da Vinci Derivatives · DRW · Common formats · Hudson River Trading · Jump Trading · Eclipse Trading · Old Mission · Belvedere Trading · Squarepoint Capital · Valkyrie Trading · Virtu Financial · Tibra · Tower Research Capital · D. E. Shaw · Mako

Practise by subject instead: topic guides.